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A 1.4 m tall girl spots a balloon moving with the wind in a horizontal line at a height of 91.4 m from the ground the angle of elevation of the balloon from the eyes of the girl at that instant is 60 degree after sometime the angle of elevation reduces to 30 degree find the distance travelled by the balloon during that interval.
take √3 = 1.732​

Answer :

103.92 metres

Step-by-step explanation:

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Answer:

105.53 m

Step-by-step explanation:

Distance covered until 60°

  • tan60° = 91.4/d₁
  • √3d₁ =91.4
  • d₁ = 91.4/1.732
  • d₁ = 52.77 m

Distance covered until 30°

  • tan30° = 91.4/d₂
  • d₂/√3 = 91.4
  • d₂ = 91.4 x 1.732
  • d₂ = 158.3 m

Distance in interval (d)

  • d₂ - d₁
  • 158.3 - 52.77
  • 105.53 m
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